Question

factorise (2a-2b)²+(2b-5c)³+(5c-3a)³​

Answer 1

Answer:

Step-by-step explanation:

 (3a - 2b)^3 + (2b - c)^3 + (c - 3a)^3 

since 

(3a - 2b) + (2b - c) + (c - 3a) = 0 

therefore 

(3a - 2b)^3 + (2b - c)^3 + (c - 3a)^3 

= 3(3a - 2b)(2b - c)(c - 3a)Source(s):if a + b + c = 0 

then a + b = -c 

cubing both sides 

(a + b)^3 = -c^3 

a^3 + b^3 + 3a^2b + 3ab^2 = -c^3 

a^3 + b^3 = -c^3 -3ab(a+b) 

a^3 + b^3 + c^3 - = 3abc [because a+b = -c]

Answer 2

https://www.symbolab.com/solver/algebra-calculator/factor%20%5Cleft(2a-2b%5Cright)%5E%7B2%7D%2B%5Cleft(2b-5c%5Cright)%5E%7B3%7D%2B%5Cleft(5c-3a%5Cright)%5E%7B3%7D%E2%80%8B