factorise (2a+3b)square-(2a-3b) square no spams
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(2a+3b)² - (2a-3b)²
Using identity a²-b² = (a+b)(a-b; we get,
[a = 2a+3b] & [b = 2a-3b]
[2a+3b+(2a-3b)] [2a+3b-(2a-3b)]
[4a] [6b]
24ab
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24ab. is the answer to ur question.
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