Factorise 2a^4b-1/4ab^4
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2 a⁴ b - 1/4 a b⁴
= a b (8 a³ - b³ ) / 4
= a b [(2a)³ - b³ ] / 4
= a b (2a - b) (4a² + 2ab + b²) / 4
= a b (8 a³ - b³ ) / 4
= a b [(2a)³ - b³ ] / 4
= a b (2a - b) (4a² + 2ab + b²) / 4
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Answer:
Ya that's the same one I got thanks
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