Question

the area of a rectangle is 120 meter square and its perimeter is 46 meter.what is the length of its diagonal

Answer 1

Area of rectangle = l×b = 120 m²
Perimeter = 2(l+b) = 46 m
=> l+b = 23 m
$Diagonal=\sqrt{l^2+b^2}$
$=\sqrt{(l+b)^2-2lb}$ 
$=\sqrt{(23)^2-2(120)}$
$=\sqrt{529-240}$
$=\sqrt{289}$
$=17$ m    Ans.