factorise (2a+b)^2-6a-3b-4
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Answered by
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Hope u like my process.
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-->(2a + b) ² - 6a - 3b - 4
= (2a +b)² - 3(2a +b) - 4
= (2a+b)² - 4(2a+b) +(2a +b) - 4
=(2a +b){(2a+b) - 4} +1{(2a+ b) - 4}
= (2a + b - 4)(2a + b +1)
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
=====================
-->(2a + b) ² - 6a - 3b - 4
= (2a +b)² - 3(2a +b) - 4
= (2a+b)² - 4(2a+b) +(2a +b) - 4
=(2a +b){(2a+b) - 4} +1{(2a+ b) - 4}
= (2a + b - 4)(2a + b +1)
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
naina92:
hey its correct...thank u
my pleasure.. Mera फर्ज़ tha
4a^2-12a+9-49b^2 factorise can u plzz solve this
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I hope it helps you..
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