Math, asked by diyaroy2, 1 year ago

prove that root 5 is irrational???????

Answers

Answered by Jacknat
11
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Answered by Anonymous
2

Let assume to the countrary , that √5 is rational



Now  



Let \bf\huge \sqrt{5} \bf\huge\frac{a}{b} where a and b are co prime  



Squaring on both sides  



5 = a^2 / b^2



5b^2 = a^2



This shows that a^2 is divisible by 5



It also shows that a is also divisible by 5



Let a = 5m for some integer m



Put a = 5m in 5b^2 = a^2



5b^2 = (5m)^2



5b^2 = 25m^2



b^2 = 5m^2



Hence



b^2 is divisible by 5  


So b is also divisible by 5



From above we can say that 5 is a common factor for both a and b



But this contradicts our assumption that a and b are co prime



Hence √5 is an irrational number . Proved


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