prove that root 5 is irrational???????
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Let assume to the countrary , that √5 is rational
Now
Let where a and b are co prime
Squaring on both sides
5 = a^2 / b^2
5b^2 = a^2
This shows that a^2 is divisible by 5
It also shows that a is also divisible by 5
Let a = 5m for some integer m
Put a = 5m in 5b^2 = a^2
5b^2 = (5m)^2
5b^2 = 25m^2
b^2 = 5m^2
Hence
b^2 is divisible by 5
So b is also divisible by 5
From above we can say that 5 is a common factor for both a and b
But this contradicts our assumption that a and b are co prime
Hence √5 is an irrational number . Proved
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