Question

factorise 2a² - 128 please solve it urgent

Answer 1

Yo mate !!!

Answer :-

=> 2a^2 - 128

= 2(a^2 - 64)

= 2(a^2 - 8^2)

= a^2 - b^2 = (a-b) (a+b)

= 2(a-8)(a+8)

Hope it helps !!!

Answer 2

Heya!
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➡Factorize =>
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=> 2a² - 128

✳Taking 2a common :-
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=> 2a ( a - 64 )


♦For the expression ( a - 64 )

=> ( a - 64 ) = (a)² - (8)²

=> ( a - 8 ) ( a + 8 )

⚫Final Expression =>>
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=> 2a ( a - 8 ) ( a + 8 )

♦Hence the Answer is =>>

=>> 2a² - 128 = 2a ( a - 8 ) ( a + 8 )

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