Question

factorise 2a²+b²+8c²- 2√2 ab + 4√2 bc - 8ac​

Answer 1

Answer

Step-by-step explanation:

(-√2a)^2+(b)^2+(c)^2+2(-√2a)(b)+2(b)(c)+2(-√2a)(c)=

(-√2a+b+c)^2=

(-√2a+b+c)(-√2a+b+c)

Answer 2

Answer:The answer is simple

Step-by-step explanation:

(-√2a)^2+(b)^2+(c)^2+2(-√2a)(b)+2(b)(c)+2(-√2a)(c)=

(-√2a+b+c)^2=

(-√2a+b+c)(-√2a+b+c)