Question

Factorise
2a3 + 4a2b + 2ab2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :-

• 2a³ + 4a²b + 2ab²

Solution :-

→ 2a³ + 4a²b + 2ab²

Take " 2a " as a common

→ 2a(a² + 2ab + b²)

Apply identity : (a + b)² = a² + b² + 2ab

→ 2a[(a)² + 2 × a × b + (b)²]

→ 2a[(a + b)²]

→ 2a(a + b)(a + b)

Some Identities :-

• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + b³ + 3ab(a + b)
• (a - b)³ = a³ - b³ - 3ab(a - b)
• a³ - b³ = (a - b)(a² + ab + b²)
• a³ + b³ = (a + b)(a² - ab + b²)