factorise 2a³-a²b-b³
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Answer:
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Answered by
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Step-by-step explanation:
Given that:-
2a³-a²b-b³
=>a³+a³-a²b-b³
=>(a³-b³)+(a³-a²b)
=>[(a-b)(a²+ab+b²)]+[a²(a-b)]
=>(a-b)[(a²+ab+b²)+(a²)]
=>(a-b)(a²+ab+b²+a²)
=>(a-b)(2a²+ab+b²)
2a³-a²b-b³=(a-b)(2a²+ab+b²)
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