Question

Factorise :2a⁴b⁴-3a²b⅝+4a²b⅝​

Answer 1

Answer:

Step-by-step explanation:

2a⁴b⁴-3a²b⅝+4a²b⅝​

= a²b⅝(2a²$b^{21/8}$-3b⅝+4$b^{27/8}$)

Answer 2

2a⁴b⁴-3a²b⅝+4a²b⅝

= a²b⅝(2a²b^{21/8}b

21/8

-3b⅝+4b^{27/8}b27/8)