Question

factorise 2ab-a^2-b^2+c^2​

Answer 1

Answer:

a2+2ab+b2-c2=a2+2ab+b2-c2

= (a+b)2-c2

=(a+b+c)(a+b-c)

Step-by-step explanation:

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Answer 2

correct question:-

Factorise:

a² −2ab+b²−c²

solution:-

$\sf \red{ a {}^{2} - 2ab + b {}^{2} - c {}^{2} } \ \\ \sf \green{(a - b) {}^{2} - c {}^{2} } (∵(x−y)²=x²−2xy+y²) \\ \sf \blue{ = (a - b + c)(a - b - c)}$.

(∵x²−y²=(x−y)(x+y))