Question

Factorise 2root 2a cube -8b cube -27c cube +18root 2 abc.

Answer 1

Answer:

Step-by-step explanation:

a^3-b^3-c^3+3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

(√2a)^3-(2b)^3-(3c)^+3*√2a*-2b*-3c=(√2a+(-2b)+(-3c)((√2a)^2+(-2b)^2+(-3c)^2-√2a*-2b-(-2b*-3c)-(-3c*√2a)

=(√2a-2b-3c)(2a^2+4b^2+9c^2-2√2ab-6bc+3√2ac)