Factorise
2x^2 /3 - 1x/3 = 1
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Answered by
6
Hi !
Solution:-
2x²/3 - x/3 = 1
=> 2x² - x/3 = 1
=> 2x² - x = 3
=> 2x² - x - 3 = 0
=> 2x² - 3x + 2x - 3 = 0
=> x ( 2x - 3) + 1 ( 2x- 3) = 0
=> ( 2x-3) (x+1) Factorised ♻
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Hope it helps you !!
@Raj❤
Anonymous:
Thanks!
Answered by
7
HEYA USER ❤️
2x²/3-1x/3=1
By taking LCM, equation will be,
2x²-x=3
2x²-x-3=0
By splitting middle term,
2x²-3x+2x-3
x(2x-3)+1(2x-3)
(x+1)(2x-3) → Required factors.
#Be_brainly❣️
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