Question

Factorise 2x^2-√3x-3​

Answer 1

Step-by-step explanation:

The first term is, 2x2 its coefficient is 2 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -3 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1

-1 + 6 = 5

Observation : No two such factors can be found !!

Thank you✨

Answer 2

Answer:

x = -√3/2 (or) √3

Step-by-step explanation:

Given that,

polynomial p(x) = 2x²-√3x-3

let, p(x) = 0

⇒ 2x²-√3x-3 = 0

(∵ the factors of 2×-3=-6 to get their sum as '-2√3' & '+√3' )

⇒ 2x²-2√3x+√3x-3 = 0

⇒ 2x(x-√3)+√3(x-√3) = 0

⇒ (2x+√3)(x-√3) = 0

Case-(1):                               Case-(2):

         ⇒ 2x+√3 = 0                         ⇒x-√3 = 0

         ⇒ 2x = -√3                            ⇒x = √3

         ⇒ x = -√3/2

∴ x = -√3/2 (or) √3

HOPE THIS WOULD BE HELPFUL FOR YOU