Question

factorise 2x^2+7x+3 find this​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 7x + 3 = 0$

$2 {x}^{2} + 6x + x + 3 = 0$

$2x(x + 3) + 1(x + 3) = 0$

$(2x + 1)(x + 3) = 0$

$\boxed{x = \frac{ - 1}{2} } \: \: \: or \: \: \: \boxed{ - 3}$

Answer 2

2x²+7x+3

= 2x²+6x+X+3

= 2x(X+3)+1(X+3)

= (2x+1)+(X+3)

= 2x=-1. OR. x=-3

=. x=-1/2. OR. x=-3