Math, asked by sharmasachin4740003, 2 months ago

factorise 2x^2y^2-8

solve it

Answers

Answered by Anonymous

0

Answer:

2(xy+2)(xy-2)

Step-by-step explanation:

2x²2y²-8

= 2(x²y²-4)

= 2[(xy)²-(2)²]

= 2(xy+2)(xy-2)

using formula x²-y² = (x+y)(x-y)

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