Question

factorise 2x^2y^2-8


solve it​

Answer 1

Answer:

2(xy+2)(xy-2)

Step-by-step explanation:

2x²2y²-8

= 2(x²y²-4)

= 2[(xy)²-(2)²]

= 2(xy+2)(xy-2)

using formula x²-y² = (x+y)(x-y)