Question

factorise 2x^2y + 2cy - 5x^2 - 5c

Answer 1

Answer:

(2y−5)(2x2+c)

Step-by-step explanation:

2x  2  2y+2cy−5x  2  2−5c

Multiply and combine like terms.

−10x  2  +4yx  2 +2cy−5c

Do the grouping −10x  2  +4yx  2

+2cy−5c=(−10x  2  +4yx  2 )+(2cy−5c), and factor out 2x  2

 in the first and c in the second group.

2x  2  (2y−5)+c(2y−5)

Factor out common term 2y−5 by using distributive property.

(2y−5)(2x  2  +c)