Math, asked by shreyart, 11 months ago

factorise :

2x^3-3x^2-11x+6

Answers

Answered by ddamu222gmailcom
1

Answer:

2*x*x*3-3*x*x*2-1*11*x+6

=6x^2-11x+6

Answered by samirafrid
2

Answer:

(x-3)(x+2)(2x-1)

Step-by-step explanation:

=2x^3-6x^2+3x^2-9x-2x+6

=2x^2(x-3)+3x(x-3)-2(x-3)

=(x-3)(2x^2+3x-2)

=(x-3){2x(x+2)-1(x+2)}

=(x-3)(x+2)(2x-1)

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