Question

factorise 2x^3 +4x^2+x-34​

Answer 1

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

0-(2*x^3-4*x^2-34*x+68)=0

Step by step solution :

STEP

1

:

Equation at the end of step 1

0-((((2•(x3))-22x2)-34x)+68) = 0

STEP

2

:

Equation at the end of step

2

:

0 - (((2x3 - 22x2) - 34x) + 68) = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

-2x3 + 4x2 + 34x - 68 =

-2 • (x3 - 2x2 - 17x + 34)

Checking for a perfect cube :

4.2 x3 - 2x2 - 17x + 34 is not a perfect cube