Question

factorise 2x^3-x^2-13x-6 Step by step batana pls​

Answer 1

Step-by-step explanation:

p(x)= 2x3-x2-13x-6

P(-2)=2(-2)^3-(-2)^2-13(-2)-6

=-16-4+26-6

=-26+26

=0

THEREFORE

x+2 is a factor of p(x)

p(x)=(x+2)(2x^2-5x-3)

=(x+2)(2x^2-6x+x-3)

=(x+2)(2x+1)(x-3)

Mark the answer as brainliest......

Answer 2

Answer:

2x³ - x² - 13x - 6 = (x + 2)(x - 3)(2x + 1)

Step-by-step explanation:

p(x) = 2x³ - x² - 13x - 6

We will use hit and trial method to find the first factor

Let x = -2

p(2) = 2(-2)³ - (-2)² - 13(-2) - 6

      =  2(-8) - 4 + 26 - 6

      = -16 - 4 + 26 - 6

p(2) = -26 + 26 = 0

x = -2         ⇒ (x + 2) is a factor of p(x).

Now divide p(x) by (x + 2)  {Long division method}

After dividing we get,

p(x) = (x + 2)(2x² - 5x - 3)

Now by splitting middle term,

p(x) = (x + 2)(2x² + x - 6x - 3)

p(x) = (x + 2)[x(2x + 1) - 3(2x + 1)]

p(x) = (x + 2)(x - 3)(2x + 1)

2x³ - x² - 13x - 6 = (x + 2)(x - 3)(2x + 1)

Therefore, the factors of p(x) are (x + 2), (x - 3) and (2x + 1).

Hope it helps.

Plz mark me as brainliest...