factorise 2x^3+x^2-7x-6
Answers
Answer:
(2x + 3)(x - 2)
Step-by-step explanation:
2x³ + x² - 7x - 6
2x³ + x² - 7x - 6let x = -1
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 1
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + c
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + cp ± q = b = -1
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + cp ± q = b = -1pq = ac = -12
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + cp ± q = b = -1pq = ac = -122x² - 4x + 3x -6
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + cp ± q = b = -1pq = ac = -122x² - 4x + 3x -62x(x - 2) +3(x - 2)
2x³ + x² - 7x - 6let x = -1or p(x) = 2x³ + x² - 7x - 6put the value of x2(-1)³ + (-1)² - 7(-1) - 6-2 + 1 + 7 - 6-1 + 10x = -1x + 1 = 0divide 2x³ + x² - 7x - 6 by x + 1= 2x² - x - 6general form: ax² + bx + cp ± q = b = -1pq = ac = -122x² - 4x + 3x -62x(x - 2) +3(x - 2) (2x + 3)(x - 2)