Question

factorise: (2x + 3y)^2 – 2(2x+3y)(3x – 2y) – 3(3x – 2y)^2
Hint: Put 2x + 3y = a and 3x – 2y = b​

Answer 1

Step-by-step explanation:

a^2-2ab-3b^2

a^2 -2ab +b^2-4ab

(a+b)^2-4b

(a+b)^2-(2√b)^2

(a+b-2√b)(a+b+2√b)