Math, asked by Rudransh98, 1 year ago

factorise 2x cube minus 3x square - 17x + 30

Answers

Answered by realsujaykumar
843
2x^3 - 3x^2 - 17x + 30
= 2x^3 - 4x^2 +x^2 -2x - 15x + 30
=2x^2(x-2) +x(x-2) -15(x-2)
=(x-2)(2x^2 +x -15)
=(x-2)(2x^2 +6x -5x -15)
=(x-2)(2x(x+3) -5(x+3))
=(x-2)(x+3)(2x-5)
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I hope this helps you....
Answered by Anonymous
9

Given : The algebraic expression is, (2x³-3x²-17x+30)

To find : Factorisation of the given algebraic expression.

Solution :

The answer to the factorisation is, (x-2) (x+3) (2x-5)

We can simply solve this mathematical problem by using the following mathematical process.

Here, we will be using general formulas and methods for doing the given factorisation. (the goal is to factorise the given algebraic expression, to the maximum possible extent.)

So,

= 2x³-3x²-17x+30

= 2x³-4x²+x²-2x-15x+30 (As, -3x² = -4x²+x², and, -17x = -2x-15x)

= 2x² (x-2) + x (x-2) - 15 (x-2)

= (x-2) (2x²+x-15)

= (x-2) (2x²+6x-5x-15) [As, x = 6x-5x]

= (x-2) {2x(x+3) - 5(x+3)}

= (x-2) (x+3) (2x-5)

(This cannot be further simplified. So, this will be considered as the final result of the given factorisation.)

Hence, the answer to the factorisation is, (x-2) (x+3) (2x-5)

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