Question

factorise 2x sqare +ysqare+8z sqare-2 root 2xy+4 root2 yz-8xz

Answer 1

I have seen you some where in u tube

2x²+y²8z²-2√2xy+4√2yz-8xz

Answer 2

Answer:

$\underline {\underline {(\sqrt{2x} -\sqrt{y} -2\sqrt{2z})}}$  and  $\underline {\underline {(\sqrt{2x} -\sqrt{y} -2\sqrt{2z})}}$

Step-by-step explanation:

Given question :

$2x^2 + y^2 + 8z^2 - 2\sqrt{2xy} + 4\sqrt{2yz} - 8xz$

Solution :

We know that

$\boxed {(a + b+c)^2 = a^2 + b^2 + c^2 +2ab + 2bc + 2ca}$

Comparing with the question, we get

$a = \sqrt{2x} \ ; \ b = -\sqrt{y} \ ; \ c = -2\sqrt{2z}$

So, we can write in the format like,

$(\sqrt{2x} -\sqrt{y} -2\sqrt{2z} )^2 = (\sqrt{2x} -\sqrt{y} -2\sqrt{2z} ) \times (\sqrt{2x} -\sqrt{y} -2\sqrt{2z} )$

Hence factors are

$\mathbf{(\sqrt{2x} -\sqrt{y} -2\sqrt{2z} ) \ and\ (\sqrt{2x} -\sqrt{y} -2\sqrt{2z} )}$

Hope it helps!