Factorise 2x square + 7 x + 3
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2x^2 + 7x + 3.
= 2x^2 + x + 6x + 3.
( splitting the middle term ).
= x ( 2x + 1 ) + 3 ( 2x + 1 ).
( taking x and 3 common ).
= (2x+1)(x+3).
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Answered by
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Answer:
2xsquare + 7x + 3
2xsquare + 6x+ 1x + 3
3x( x+ 3) 1( x + 3)
3x + 1 or x+ 3
3x+ 1 = 0 or x + 3 = 0
3x= -1 or x = -3
x = -1/3 or x = -3
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