factorise (2x-y)³-2x+y
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Step-by-step explanation:
(2x-y)^3-(2x-y)
=(2x-y)[2x-y)^2-1] {1 can also be represented by 1^2)
=(2x-y)(2x-y+1)(2x-y-1) {by the formula a^2-b^2=(a+b)(a-b)}
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