Question

factorise:2x²+y²+2z²-2√2xy+2√2yz-4xz and 8x²+13x-6​

Answer 1

Answer:

$2x ^{2} + y ^{2} + 2z ^{2} - 2 \sqrt{2xy} + 2 \sqrt{2yz} - 4xz \\ ( \sqrt{2x} )^{2} + (y)^{2} + ( \sqrt{2z} )^{2} + 2 \times \sqrt{2} x \times y + 2 \times y \times \sqrt{2z} + 2 \times \sqrt{2z} \times \sqrt{2x} \\ ( \sqrt{2} x + y + \sqrt{2} z) ^{2}$

Step-by-step explanation:

$8x^{2} + 13x - 6 \\ 8x^{2} + 16x - 3x - 6 \\ 8x(x + 2) - 3(x + 2) \\ (x + 2) (8x - 3)$