Question

factorise 2x³-x²+x-2

Answer 1

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$\underline\bold{\huge{ANSWER \: :}}$

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2x³-x²+x-2

= 2x³-2-x²+x

= 2(x³-1)-x(x-1)

= {2 (x-1) (x²+x+1)} - x(x-1)

= (x-1) ([2 (x²+x+1)] - x)

= (x-1) (2x²+2x+2-x)

= (x-1) (2x²+x+2) [ANSWER]

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Answer 2

❤ HERE IS YOUR ANSWER ❤

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2x³-x²+x-2

= 2x³-2-x²+x

= 2(x³-1)-x(x-1)

= {2 (x-1) (x²+x+1)} - x(x-1)

= (x-1) ([2 (x²+x+1)] - x)

= (x-1) (2x²+2x+2-x)

= (x-1) (2x²+x+2)

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Hence, your required answer is :

( x - 1 ) ( 2x² + x + 2 )

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