Question

Factorise 


(2x5) (3x-2) (x2) (2x-3) 

Answer 1

HEY!!

[(2x+5)(3x-2)] + [(x+2)(2x-3)]
= [2x (3x-2) + 5 (3x-2)] + [x (2x-3) + 2(2x-3)]
= [6x^2 - 4x + 8x - 10] + [2x^2 - 3x +4x - 6]
= [6x^2 + 4x - 10] + [2x^2 + x - 6]
= 6x^2 + 4x - 10 + 2x^2 +x - 6
= 6x^2 + 2x^2 + 4x + x -10 - 6
= 8x^2 + 5x -16

Answer 2

hy
here is your answer
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[(2x+5)(3x-2)] + [(x+2)(2x-3)]

= [2x (3x-2) + 5 (3x-2)] + [x (2x-3) + 2(2x-3)]

= [6x²- 4x + 8x - 10] + [2x² - 3x +4x - 6]

= [6x² + 4x - 10] + [2x² + x - 6]

= 6x² + 4x - 10 + 2x² +x - 6

= 6x² + 2x² + 4x + x -10 - 6

= 8x²+ 5x -16
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