Question

Factorise 3√2x^2+11x+4√2​

Answer 1

Answer:

3x(√2x+1) +4√2(√2x+1) = (3x+4√2)(√2x+1)

Answer 2

Answer:

$x=\frac{-1}{\sqrt{2} }$, $\frac{-4\sqrt{2} }{3}$

Step-by-step explanation:

By splitting the middle term, [please refer the attachment below to see he factors]

$3\sqrt{2} x^{2} +11x+4\sqrt{2}$

$3\sqrt{2} x^{2} +8x+3x+4\sqrt{2}$

$\sqrt{2}x (3x+4\sqrt{2} )+ 1(3x+4\sqrt{2} )$

$(\sqrt{2}x+1)(3x+4\sqrt{2} )$

$\sqrt{2}x+1=0$              $3x+4\sqrt{2}=0$

$\sqrt{2}x = -1$                   $3x=-4\sqrt{2}$

∴ $x=\frac{-1}{\sqrt{2} }$                     ∴ $x = \frac{-4\sqrt{2} }{3}$

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