Question

factorise 3. a(b - c)2 - d(c-b)​

Answer 1

Answer:

Step-by-step explanation:

se 3. a(b - c)2 - d(c-b)​

Answer 2

Given equation,

$a(b - c)2 - d(c-b)$

Here we have to factorize the given equation,

Multiply the terms which are out of the brackets.

We get,

$(ab-ac)2-dc+bd$

$2ab-2ac-dc+bd$

Rearrange the equation to take some common terms

We get the equation after rearranging as,

$2ab+bd-2ac-dc$

Take $b$ common in first two terms and $-c$ from last two terms.

$b(2a+d)-c(2a+d)$

Also take $(2a+d)$ common from both the terms.

$(2a+d)(b-c)$

Therefore, the final answer after factorization is $(2a+d)(b-c)$