factorise (3+x)^2 – 64x^2
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Answer:
(3+x)²-64x².
(3+x)².
It is in the form of (a+b)²=a²+b²+2ab where a=3 & b=x.
(3+x)²=(3)²+(x)²+2(3)(x).
=9+x²+6x.
(3+x)²-64x²=9+x²+6x-64x².
=9+6x-63x².
I think this is your answer.
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