Factorise
3 (x+y) ² - 5x(x+y ) +2
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Answer:
Consider, 3(x + y)2 – 5(x + y) + 2 = 3(x + y)2 – 3(x + y) – 2(x + y) + 2 = 3(x + y)[(x + y) – 1] – 2[(x + y) – 1] = [(x + y) – 1][3(x + y) – 2] = [x + y – 1][3x + 3y – 2]
Answered by
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Consider, 3(x + y)2 – 5(x + y) + 2
= 3(x + y)2 – 3(x + y) – 2(x + y) + 2
= 3(x + y)[(x + y) – 1] – 2[(x + y) – 1]
= [(x + y) – 1][3(x + y) – 2]
= [x + y – 1][3x + 3y – 2]
hope it hlps uh
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