factorise 343a^3-b^3-147a^2b+21ab^2
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Answer:
343a³-b³-147a²b+21ab² = (7a-b) ³
Step-by-step explanation:
a³-b³-3(a²b-ab²) = (a-b) ³
343a³-b³-147a²b+21ab²
= (7a)³-b³-[3(49a²b) -3(7ab²)]
= (7a)³-b³-3[(49a²b) -(7ab²)]
= (7a-b) ³
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