Question

factorise 365 y4 z3 - 146 y2 z4

Answer 1

Factorization of $365 y^4.z^3 - 146 y^2.z^4$ = 73.y².z² [(5.y²- 2.z)].

To factorize : The given number $365 y^4.z^3 - 146 y^2.z^4$

Given data :    

$365 y^4.z^3 - 146 y^2.z^4$

365 can be written as " 5 × 73 ".

146 can be written as " 2 × 73 ".

$y^4$ ⇒ $y^2$ × $y^2$

$z^4$ ⇒ $z^2$ × $z^2$

$365 y^4.z^3 - 146 y^2.z^4$ = (5 × 73 ×  $y^2$ × $y^2$ × z³) - (2 × 73 × $y^2$ × z³ × z)

Take the common terms,

$365 y^4.z^3 - 146 y^2.z^4$ = (5 × 73 ×  $y^2$ × $y^2$ × z³) - (2 × 73 × $y^2$ × z³ × z)

                               = 73 × $y^2$ × z³ ((5 × $y^2$) - (2 × z)

                               =  73.y².z² [5.y² -  2.z]        

Hence, the factorization of $365 y^4.z^3 - 146 y^2.z^4$ is 73.y².z²[(5.y² - 2.z)].

 

To learn more...

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