Question

Factorise (3a-b) ² - 9 c²​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :

›»› (3a - b)² - 9c² = (3a - b - 3c) (3a - b + 3c)

Given :

• (3a - b)² - 9c²

To Find :

• Factorize the expression.

Required Solution :

Let's start solving the problem and understand the steps to get our final result$.$

⇛ (3a - b)² - 9c²

Present as the shape of the power,

⇛ (3a - b)² - (3²c²)

Binding the power,

⇛ (3a - b)² - (3c)²

Organize by using A² - B² = (A - B) (A - B),

⇛ ((3a - b) + 3c) ((3a - b) - (3c))

Get rid of unnecessary parentheses,

⇛ (3a - b) + 3c) ((3a - b) - (3c))

Get rid of unnecessary parentheses,

⇛ (3a - b) + 3c) (3a - b - (3c))

Release the parentheses,

⇛ (3a - b) + 3c) (3a - b - 3c)

Sort the factors,

⇛ (3a - b - 3c) (3a - b + 3c)

║Hence, the factorization of (3a - b)² - 9c² is (3a - b - 3c) (3a - b + 3c).║