Math, asked by jd10, 7 months ago

Factorise (3a - b)^2-9c^2

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Answered by ashim8

${(3a - b)}^{2} - {9c}^{2} \\ = {(3a - b)}^{2} - {3c}^{2} \\ thus \: by \: solving \: using \: \\ (a + b)(a - b) = {a}^{2}- {b}^{2}\\(3a - b + 3c) (3a - b - 3c)$

Thus your answer is ready

Answered by rawatashish18872

(3a-b)^2-9c^2
((3a-b)+9c)((3a-b)-9c)

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Factorise (3a - b)^2-9c^2​

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Factorise (3a - b)^2-9c^2