Question

factorise 3ab(X2+y2)+xy(3a2+3b2)

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Answer 1

Step-by-step explanation:

Given that:-

3ab(x²+y²)+xy(3a²+3b²)

=>3ab(x²+y²)+3xy(a²+b²)

=>3[ab(x²+y²)+xy(a²+b²)]

=>3[abx²+aby²+a²xy+b²xy]

=>3[(abx²+a²xy)+(aby²+b²xy)]

=>3[ax(bx+ay)+by(ay+bx)]

=>3[(ay+bx)(ax+by)]

=>3(ax+by)(bx+ay)

3ab(x²+y²)+xy(3a²+3b²)=3(ax+by)(bx+ay)