Question

factorise 3n^2-n-494​

Answer 1

Answer:

494 Cannot come it may be only 4

Step-by-step explanation:

Factoring 3n2-n-4

The first term is, 3n2 its coefficient is 3 .

The middle term is, -n its coefficient is -1 .

The last term, "the constant", is -4

Step-1 : Multiply the coefficient of the first term by the constant 3 • -4 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -1 .

-12 + 1 = -11

-6 + 2 = -4

-4 + 3 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 3

3n2 - 4n + 3n - 4

Step-4 : Add up the first 2 terms, pulling out like factors :

n • (3n-4)

Add up the last 2 terms, pulling out common factors :

1 • (3n-4)

Step-5 : Add up the four terms of step 4 :

(n+1) • (3n-4)

Which is the desired factorization

Answer 2

Step-by-step explanation:

please mark as brainliest