Question

Factorise: 3x^2-2√6x +2=0

Answer 1

i think u can understand this

Answer 2

↦Solution : -

3x² - 2√6x + 2 = 3x² - √6x - √6x + 2

√3x (√3x - √2) - √2 (√3x - √2)

(√3x - √2) (√3x - √2)

So , the roots of the equation are the values of x for which ,

(√3x - √2) (√3x - √2) = 0

Now ,

√3x - √2 = 0 for x = √2/3

So , this root is repeated twice, one for each repeated factor √3x - √2

Hence , the roots of 3x² - 2√6x + 2 = 0 are √2/3 , √2/3 ..