Question

factorise 3x^2-5x-8​

Answer 1

3x^2-8x+3x-8

x(3x-8)+1(3x-8)

(x+1)(3x-8)

Answer 2

Hęřę įš ùř ąńšwęř....♥♡♥

$= > 3 {x}^{2} - 5x - 8 = 0$

$= > 3 {x}^{2} - 8x + 3x - 8 = 0$

$= > x(3x - 8) + 1(3x - 8) = 0$

$= > (x + 1)(3x - 8) = 0$

Hence,

x+1=0 or 3x-8=0

$x = - 1 \: or \: x = \frac{8}{3}$