factorise 3x cube-x square-3x+1
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Answered by
1
Answer:
HEY USER !!
HERE IS UR ANSWER --
3x^3 - x^2 - 3x + 1
= x^2 ( 3x - 1 ) - 1 ( 3x - 1 )
= ( 3x - 1 ) ( x^2 - 1 )
= ( 3x - 1 ) [ (x)^2 - (1)^2 ]
= ( 3x - 1 ) [ (x + 1) (x - 1)]
Answered by
5
hey mate:
find here
=3x³-x²-3x+
=3x³-3x²+2x²-2x-x+1
=3x²(x-1)-2x(x-1)-1(x-1)
=(x-1)(3x²-2x-1
=x-1)(3x²-3x+x-1)
=(x-1)(3x(x-1)+1(x+1)
=(x-1)(3x+1)(x-1)
thus:
factories will be
(x-1)(3x+1)(x-1)
i hopes its helps u
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