Factorise:- 3x³ - 17x² + 18x +8
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Answered by
20
3x^3-17x^2+18x+8=0
=> 3x^3-6x^2-11x^2+22x-4x+8=0
=> 3x^2 (x-2)-11x (x-2)-2 (x-2)=0
=> (3x^2-11x-2)(x-2)=0
3x^2-11x-2=0 and x-2=0
3x^2-11x-2=0 is factorise by quadratic formula .
hence
x=(11+root(145))/6, (11-root (145))/6, and 2
=> 3x^3-6x^2-11x^2+22x-4x+8=0
=> 3x^2 (x-2)-11x (x-2)-2 (x-2)=0
=> (3x^2-11x-2)(x-2)=0
3x^2-11x-2=0 and x-2=0
3x^2-11x-2=0 is factorise by quadratic formula .
hence
x=(11+root(145))/6, (11-root (145))/6, and 2
abhi178:
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Answered by
3
Answer:
x=4
x=2
x=-1/3
Step-by-step explanation:
x=4
x=2
x=-1/3
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