Find the equation of a line passing through the point of intersection of 4x+2y=7 with the y-axis and parallel to y-7x+5=0
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Answered by
36
intersection between 4x+2y=7 and y-axis i.e. x=0
put x=0 in 4x+2y=7
y=7/2
hence point of inersection is (0,7/2)
now unknown equation parellel to
y-7x+5=0
slope of unknown line =slope of above line =7
now equation of line
(y-7/2)=7 (x-0)
7x-y+7/2=0
14x-2y+7=0
put x=0 in 4x+2y=7
y=7/2
hence point of inersection is (0,7/2)
now unknown equation parellel to
y-7x+5=0
slope of unknown line =slope of above line =7
now equation of line
(y-7/2)=7 (x-0)
7x-y+7/2=0
14x-2y+7=0
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Answered by
8
Answer:
Step-by-step explanation:intersection between 4x+2y=7 and y-axis i.e. x=0
put x=0 in 4x+2y=7
y=7/2
hence point of inersection is (0,7/2)
now unknown equation parellel to
y-7x+5=0
slope of unknown line =slope of above line =7
now equation of line
(y-7/2)=7 (x-0)
7x-y+7/2=0
14x-2y+7=0
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