Question

factorise 3y^2+12y-63


need the whole process


yeah tia I checked it on web but I couldn't find any result​

Answer 1

Answer:

3(y-3)(y+7)

Step-by-step explanation:

First, take 3 as common and it will become, 3(y^2+4y-21)

3(y^2-7y+3y-7*3)

3(y-3)(y+7)

Hope it helped... :)

Answer 2

Answer:

3(y + 7)(y - 3)

Step-by-step explanation:

3y² + 12y - 63

( taking 3 as common )

3[ y² + 4y - 21]

Product = 21 × 1 = 21

sum => 7, (-3)

y² + 7y - 3y - 21

y(y + 7) -3(y + 7)

= 3(y + 7)(y - 3)

hope it will help you