factorise:- 3Y^2+14Y+8
Answers
Answered by
4
Answer:
Factorise :- 3y²+14y+8
Solution:-
3y²+14y+8
= 3y²+(12+2)y+8. [Mid term factorisation]
= 3y²+12y+2y+8.
= 3y(y+4)+2(y+4)
= (y+4)(3y+2)
Ans:- 3y²+14y+8= (y+4)(3y+2)
❥︎hope it works out for you and please f-o-l-l-o-w me and Mark me brainliest and thanks my answers
꧁Prapti꧂
Answered by
1
Answer:
3y^2 +14y+8
first multiply the y^2 (3) coefficient with 8
then 3y^2+14y+8
3y^2+12y+2y+8
3y(y+4) +2(y+4)
(3y+2) (y+4)
Thank you
Similar questions