Math, asked by akshayajeet8743, 5 hours ago

factorise:- 3Y^2+14Y+8​

Answers

Answered by SweetPrapti
4

Answer:

Factorise :- 3y²+14y+8

Solution:-

3y²+14y+8

= 3y²+(12+2)y+8. [Mid term factorisation]

= 3y²+12y+2y+8.

= 3y(y+4)+2(y+4)

= (y+4)(3y+2)

Ans:- 3y²+14y+8= (y+4)(3y+2)

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Prapti

Answered by garlapatiswarooparan
1

Answer:

3y^2 +14y+8

first multiply the y^2 (3) coefficient with 8

then 3y^2+14y+8

3y^2+12y+2y+8

3y(y+4) +2(y+4)

(3y+2) (y+4)

Thank you

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