Question

Factorise
3y^3+2y^2-5y-6

Answer 1

Answer:

3y³+2y²-5y-6

Taking common

y(3y²+2y-5)-6

y(3y²-3y+5y-5)-6

y(3y(y-1)+5(y-1))-6

y(y-1)(3y+5)-6

hope this helps you

Answer 2

ANSWER :

We have,

3y^3 + 2y^2 - 5y - 6

So,

y (3y^2 + 2y - 5) - 6

HERE WE WILL USE 'SPLITTING THE MIDDLE' METHOD

we will split '2y'.

p×q = 3y^2 × -5 (about this I have doubt sorry about that.)

p+q = 2y

HERE, p = -3y and q = 5y

y (3y^2 - 3y + 5y - 5) - 6

y [3y(y-1) + 5(y-1)] - 6

y(3y+5)(y-1) - 6.

I HOPE ,

YOU LIKED MY ANSWER