Question

factorise
3y^3+2y^2-5y-6​

Answer 1

Answer:

Step-by-step explanation:

Given  

factorize 3 y^3+2 y^2-5 y-6

ANSWER

First we need to group the given equation.

So y (3 y^2 + 2 y – 5) – 6

So we have  

     Y (3 y^2 – 3 y + 5 y - 5) – 6

  Y [3 y(y – 1) + 5(y – 1)] – 6

  Y ( 3 y + 5)(y – 1) - 6

Answer 2

ANSWER :

We have,

3y^3 + 2y^2 - 5y - 6

So,

y (3y^2 + 2y - 5) - 6

HERE WE WILL USE 'SPLITTING THE MIDDLE' METHOD

we will split '2y'.

p×q = 3y^2 × -5 (about this I have doubt sorry about that.)

p+q = 2y

HERE, p = -3y and q = 5y

y (3y^2 - 3y + 5y - 5) - 6

y [3y(y-1) + 5(y-1)] - 6

y(3y+5)(y-1) - 6.

I HOPE ,

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