Question

factorise 3y^4-243 using identity from class 9 ch 2 polynomials​

Answer 1

The given expression is

$= 3 {y}^{4} - 243$

$= 3( {y}^{4} - 81)$

$= 3( ({ {y}^{2} })^{2} - {9}^{2} )$

$= 3( {y}^{2} + 9)( {y}^{2} - 9)$

$= 3( {y}^{2} + 9)( {y}^{2} - {3}^{2} )$

$= 3( {y}^{2} + 9)(y + 3)(y - 3)$

Answer 2

Answer:

hope it helps ✌️✌️✌️✌️✌️